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- #include<bits/stdc++.h>
- using namespace std;
- //问题 G: 所有情况的和 S1=a1+b1;S2=(a1+b1)(a2+b2); Sn=(a1+b1)***(an+bn)
- const int MOD = 1e9 + 7;
- typedef long long LL;
- int main() {
- for (int T; cin >> T;) {
- LL s = 1;
- while (T--) {
- int a, b;
- cin >> a >> b;
- s = (s * (a + b)) % MOD;
- }
- cout << s << endl;
- }
- return 0;
- }
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